Calendar problems can be solved by the concept of odd days.
Odd Days : Number of days remained that are more than complete week cycles. For 10 days, 3 odd days are there (1 week + 3 days).
For 15 days, 1 odd day (2 weeks + 1 day).
Month |
Days |
Weeks |
Odd Days |
January |
31 |
4 |
3 |
February |
28 |
4 |
0 (ordinary); 1 (Leap) |
March |
31 |
4 |
3 |
April |
30 |
4 |
2 |
May |
31 |
4 |
3 |
June |
30 |
4 |
2 |
July |
31 |
4 |
3 |
August |
31 |
4 |
3 |
September |
30 |
4 |
2 |
October |
31 |
4 |
3 |
November |
30 |
4 |
2 |
December |
31 |
4 |
3 |
1600 Years = 0 Odd Days |
300 Years = 1 Odd Day |
Day |
Odd Days |
Sunday |
0 |
Monday |
1 |
Tuesday |
2 |
Wednesday |
3 |
Thursday |
4 |
Friday |
5 |
Saturday |
6 |
- Ordinary Year : Has 365 days. 1 Odd day (52 weeks + 1 day).
- Leap Year : Has 366 days. 2 Odd days (52 weeks + 2 days).
- Every 4th century is a leap year except other centuries. 400, 800, 1200, 1600, 2000 etc. leap year.